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2005/03/16 | CLR电路[CLR Circuit]
类别(Ω〖物理〗)
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(0)
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阅读(55)
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发表于 15:33
Given an
electric circuit
composed of an
inductor
with
inductance
L
, a
resistor
with
resistance
R
, and a
capacitor
with
capacitance
C
, the
Kirchhoff loop rule
requires that the sum of the changes in potential around the circuit must be zero, so
(1)
where
I
is the
current
through the
inductor
,
resistor
and
Q
is the
charge
on the
capacitor
, and
t
is the elapsed time. Differentiating gives
(2)
which can be rewritten
(3)
Now define the variables
(4)
(5)
to write the differential equation in the standard form
(6)
Here
is the
differential operator
.
As in any
simple harmonic motion
,there are three classes of solution depending on the sign of
: underdamped, critically damped, and overdamped. For an underdamped circuit,
(7)
which is equivalent to
(8)
and the
simple harmonic motion
solution is
(9)
where
(10)
and
For a critically damped circuit
(11)
which is equivalent to
(12)
and the solution is
(13)
where
For an overdamped circuit,
(14)
or
(15)
The solution is
(16)
where
giving
and the constants are given by
For a sinusoidally driven CLR circuit, define
(17)
(18)
(19)
(20)
(21)
where
is the
permittivity of free space
. The equations are
(22)
(23)
(24)
(25)
The problem can be solved by solving the differential equation. However, it is much simpler to assume a harmonic solution
(26)
Use complex
impedance
to find the solution of this type, if it exists
(27)
So the harmonic solution is
(28)
where
(29)
(30)
Dividing by
CL
,
(30)
(32)
(33)
The homogeneous solution will be underdamped, critically, or overdamped depending on the initial conditions. However, it will be exponentially decaying, so the steady state solution is given be the solution above. The maximum
of
(34)
occurs at
(35)
Furthermore, at
,
, so
(36)
]
(37)
but
(38)
so
(39)
Both
and
are maximum at
, so
(40)
To find the half-power points, solve
(41)
(42)
(43)
(44)
(45)
(46)
The full width at half maximum is
The amplitude decay time is
(48)
The
energy
stored in the system is
(49)
(50)
so
(51)
(52)
(53)
Q
is a minimum when
(54)
(55)
Note that near resonance,
(56)
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